public static void main(String[] args) 
{
   String Test = "ABCAAABCD";
   String dummy = ""; 
		
   String[] arrTest = Test.split("");
		
   List<String> seenChars = new ArrayList<String>();
   List<String> subStrings = new ArrayList<String>();
		
   int j = 0;
		
   for (int i = 1; i < arrTest.length; i++) 
   {
      if(seenChars.contains(arrTest[i]))
      {
	 subStrings.add(dummy);
	 dummy = "";
	 seenChars.clear();
      }
			
      seenChars.add(arrTest[i]);
      dummy += arrTest[i];
			
       j = i + 1;
			
       if(j == arrTest.length)
	  subStrings.add(dummy);
   }
		
   int highestNo = 0;
   int lastHighest = 0;
   int currHighestNo = 0;
   int highestPOS = 0;
	
   for(int k = 0; k < subStrings.size() ; k++)
   {
	currHighestNo = subStrings.get(k).length();
		
	if(currHighestNo  > lastHighest)
	{
  	  highestNo = currHighestNo;
	  highestPOS = k;
	}		
	  lastHighest = currHighestNo;
	}
		
	System.out.println(subStrings.get(highestPOS));		
}

Method 2

public static void main(String args[]) 
{
	String Test = "ABCDEAAABCDA";
	String dummy = "";

	String[] arrTest = Test.split("");
	String longestSubString = "";

	List<String> seenChars  = new ArrayList<String>();
	List<String> subStrings = new ArrayList<String>();

	for (String strTest : arrTest) 
	{
		if (seenChars.contains(strTest)) 
		{
			if (dummy.length() > longestSubString.length())
				longestSubString = dummy;

			subStrings.add(dummy);
			dummy = "";
			seenChars.clear();
		}
		
		seenChars.add(strTest);
		dummy += strTest;
	}
	
	if (dummy.length() > longestSubString.length())
	{
		longestSubString = dummy;		
		subStrings.add(dummy);	
	}
	 
	System.out.println("Longest subString is: " + "'" + longestSubString + "'" + " and length is: "
			+ longestSubString.length());
}

Input

MUGIL XXX

Output

MXUXGXIL
public class Array1 
{
 static List arrNewList1 = new ArrayList();
 
 public static void main(String[] args) 
 { 
   String text1 = "MUGIL";
   String text2 = "XXX"; 
 
   String[] arrList1 = text1.split("");
   String[] arrList2 = text2.split("");
 
   if(arrList2.length > arrList1.length)
    swapArrays(arrList2, arrList1);
   else 
    swapArrays(arrList1, arrList2);

 
 
   StringBuilder strBr = new StringBuilder();
 
   for (int i = 0; i < arrNewList1.size(); i++) 
    strBr.append(arrNewList1.get(i));
 
    System.out.println(strBr); 
 }
 
 public static void swapArrays(String[] pBigList, String[] pSmallList)
 { 
   for (int i = 0; i < pBigList.length; i++) 
   { 
     arrNewList1.add(pBigList[i]);
 
     if(i < pSmallList.length)
      arrNewList1.add(pSmallList[i]);
   }
 }
}

Note

 .
 .
 String Text1 = "M,U,G,I,L";
 String Text2 = "MUGIL";
		
 System.out.println(Text1.split(",").length);
 System.out.println(Text2.split("").length);
 .
 .

Output

5
6

you may be puzzled why first prints 5 and second prints 6.Thats because the empty space between “M is taken as 1 element in Text2

Input and Output

{1,2,3,4}{2,3}  -> true
{1,2,3,4}{2,5}  -> false
{2,3}{2,5,6}    -> false
{2,3}{2,3,9}    -> false
public boolean checkEquals()
{
  Integer orig[] = {1,2,3,4};
  Integer act[] = {2,3};
			    
  List origList = new ArrayList(Arrays.asList(orig));
  List actList = Arrays.asList(act);
	
  origList.retainAll(actList);
  System.out.println(origList);
	   
  if(actList.size()==origList.size())	   
    return true;
  else
    return false;  
}

Check Palindrome

 public static void main(String args[])
 {
      String original, reverse = "";
      original = "madam";
 
      int length = original.length();
 
      for ( int i = length - 1; i >= 0; i-- )
         reverse = reverse + original.charAt(i);
 
      if (original.equals(reverse))
         System.out.println("Entered string is a palindrome.");
      else
         System.out.println("Entered string is not a palindrome."); 
  }

Fibonacci(without using recursion)

public class Test
{
  public static void main(String[] args)
  {
     int a=0 , b=0 , c=1;
     System.out.println(a);
     System.out.println(b);

     for(int i=0;i<15;i++)
     {
        a=b;
        b=c;
        c=a+b;
        System.out.println(c);
     }
   }
}

Fibonacci(using recursion)

7

Reverse array without Temp Array

public static int[] reverseArrayWithoutTempArray(int[] array) 
{
    int i = 0, j = array.length - 1;
 
    for (i = 0; i < array.length / 2; i++, j--) 
    {
        int temp = array[i];
        array[i] = array[j];
        array[j] = temp;
    }
    return array;
}